In a differential amplifier, if input 1 received a voltage of +50 microvolts and input 2 a voltage of -100 microvolts, what would be the approximate output voltage?

In a differential amplifier, the output voltage is determined by the difference between the two input voltages. The formula for the output voltage ( V_{out} ) in a differential amplifier can be expressed as:

[

V_{out} = A \times (V_{+} - V_{-})

]

Where ( A ) is the gain of the amplifier, ( V_{+} ) is the voltage at input 1, and ( V_{-} ) is the voltage at input 2.

In the given scenario, input 1 has a voltage of +50 microvolts, and input 2 has a voltage of -100 microvolts. To find the difference:

[

V_{+} - V_{-} = 50 , \mu V - (-100 , \mu V) = 50 , \mu V + 100 , \mu V = 150 , \mu V

]

Assuming a gain of 1 for simplicity (which is common in basic calculations unless stated otherwise), the output voltage would thus be 150 microvolts. Since input 2 is negative and contributes to an increase in the output relative to input 1