ABRET Digital Instrumentation Practice Test

In a differential amplifier, the output voltage is determined by the difference between the two input voltages. The formula for the output voltage \( V_{out} \) in a differential amplifier can be expressed as:

\[

V_{out} = A \times (V_{+} - V_{-})

\]

Where \( A \) is the gain of the amplifier, \( V_{+} \) is the voltage at input 1, and \( V_{-} \) is the voltage at input 2.

In the given scenario, input 1 has a voltage of +50 microvolts, and input 2 has a voltage of -100 microvolts. To find the difference:

\[

V_{+} - V_{-} = 50 \, \mu V - (-100 \, \mu V) = 50 \, \mu V + 100 \, \mu V = 150 \, \mu V

\]

Assuming a gain of 1 for simplicity (which is common in basic calculations unless stated otherwise), the output voltage would thus be 150 microvolts. Since input 2 is negative and contributes to an increase in the output relative to input 1